Question

What is the value of 3x^2+4y^2 if x=2,y=1 and z=-3

Answer 1

16

Step-by-step explanation

The given expression is;

`3 {x}^(2) + 4 {y}^(2)`

If x=2, y=1 and z=-3, we substitute the values into the expression and solve.

We substitute to obtain;

`3 {(2)}^(2) + 4 {(1)}^(2)`

We evaluate to get;

`3 {(4)} + 4 {(1)}`

We multiply out to get:

`12+ 4 = 16`

Therefore the value of the given expression is with the given values is 16