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What is the complete factorization of the polynomial below? X^3+3x^2-x-3

1 Answer

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Answer:

(x + 3)(x + 1)(x - 1)

Explanation:

Given

x³ + 3x² - x - 3

Factor the first/second and third/fourth terms

= x²(x + 3) - 1(x + 3) ← factor out (x + 3) from each term

= (x + 3)(x² - 1) ← (x² - 1) is a difference of squares, hence

= (x + 3)(x + 1)(x - 1) ← in factored form

User Jon Robinson
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