Question

Find the eighth term of the

geometric sequence, given the
first term and common ratio.
a1=6 and r=-1/3


PLEASE HELP

Answer 1

see explanation

Explanation:

The n th term of a geometric sequence is

`a_(n)` = a₁
`(r)^(n-1)`

where a₁ is the first term and r the common ratio, hence

`a_(8)` = 6 ×
`(-1/3)^(7)` = 6 × -
`(1)/(3^(7) )` = 6 × -
`(1)/(2187)` = -
`(2)/(729)`