"a sample of helium gas at 27.0 °c and 4.20 atm pressure is cooled in the same container to a temperature of -73.0 °c. what is the new pressure?"

asked Sep 4, 2020 111k views

4 votes

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2 votes

Answer: 2.80 Atm

Step-by-step explanation:

Gay-lussac's law

P1÷T1=P2÷T2

T2·P1÷T1

(200)·(4.20)÷300

Derorrist answered Sep 9, 2020

6.6k points

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