Answer:
There will be approx 283908 hits.
Explanation:
A website had 342,000 hits in 2011.
This is a decline of 2.3% from the previous year.
Decline rate = 2.3% or 0.023
So, increase rate will be
![1-.023=0.977](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sqp0xh468dsfybjkwo77jswtlv1i01n9fu.png)
Time =
![2019-2011=8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3b1xvw36azfg94xsz9k9cnyd9v5r5rhuql.png)
We can calculate the answer as:
![342000*(0.977)^(8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jetjizl4ym6qdbwxz1yhif8l6tp9s7ppgx.png)
=
![342000*0.83014](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xky0b50mj9jcg8mql4vtq8rc0bp6hi17ih.png)
= 283907.88 rounding to 283908.
Therefore, there will be approx 283908 hits.