Question

How to simplify this algebra​

Answer 1

`\large\boxed{A.\ (1)/(x^2y^2)}`

Explanation:

`(x^0y^(-3))/(x^2y^(-1))=(1\cdot(1)/(y^3))/(x^2\cdot(1)/(y))=1\cdot(1)/(y^3)\cdot(1)/(x^2)\cdot(y)/(1)=(1)/(y^2x^2)`

`\text{Used}\\\\a^0=1\ \text{for all real numbers except 0}\\\\a^(-n)=(1)/(a^n)`

Answer 2

x^0 = 1 because anything to the power of 0 is equal to 1

Negative exponents mean that the base is on the wrong side of the fraction line

A is correct