Answer:
C) 3.0 joules
Step-by-step explanation:
The kinetic energy of the ball is given by:
![K=(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/physics/middle-school/c6fs3acuplloc3whu5cpc8ui63cnl7ur39.png)
where
m = 0.059 kg is the mass of the ball
v is its speed
At the beginning, v = 26 m/s, so the initial kinetic energy is
![K=(1)/(2)(0.059 kg)(26 m/s)^2=20 J](https://img.qammunity.org/2020/formulas/physics/high-school/b75uv2lu2pq9tvtoakc3lij7arp1b2p8cm.png)
after the rebound, v = 24 m/s, so the final kinetic energy is
![K=(1)/(2)(0.059 kg)(24 m/s)^2=17 J](https://img.qammunity.org/2020/formulas/physics/high-school/31v84q8t6grymlq76nb1p6794ji5qm6vwv.png)
So, the energy that was lost is
![E=20 J-17 J=3 J](https://img.qammunity.org/2020/formulas/physics/high-school/g7kj2eqjd2zh3ma05fh0ru9qabuc9hoswa.png)