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Some one please help

Some one please help-example-1

1 Answer

2 votes

Answer: d

|4x + 1| ≤ 5

⇒ - 5 ≤ 4x + 1 ≤ 5

⇔ -6 ≤ 4x ≤ 4

⇔ -1.5 ≤ x ≤ 1

⇒ x ∈ [-1.5; 1]

Explanation:

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