2 Answers

Matt Ranney · Answer 1 · 2020-08-27T23:36:01+0000

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

$m = \frac {y2-y1} {x2-x1}$

We have the following points:
$(x1, y1) :( 5,6)\\(x2, y2) :( 4,8)$

Substituting:

$m = \frac {8-6} {4-5}\\m = \frac {2} {- 1}\\m = -2$

Then, the equation is:

y = -2x + b

To find "b" we substitute one of the points:

$8 = -2 (4) + b\\8 = -8 + b\\b = 8 + 8\\b = 16$

Finally, the equation is:

y = -2x + 16

Answer:

Option B

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