Question

What are the roots of the function f(x)=x^2+x-6

A. X=3 and x= -2
B. X= -3 and x= -6
C. X=1 and x=-6

Answer 1

None of the above

Explanation:

A is the closest but it should be 2 and -3

Answer 2

For this case we have the following quadratic function:

`f (x) = x ^ 2 + x-6`

We must find its roots. We can factor, looking for two numbers that when added to +1 and multiplied by -6. These are:

+3 and -2

`+ 3-2 = 1\\(+3) * (- 2) = - 6`

Then, the factored form is:

`(x + 3) (x-2) = 0`

So, the roots are:

`x_ {1} = - 3\\x_ {2} = 2`

Answer:

`x_ {1} = - 3\\x_ {2} = 2`