Answer : The correct option is,
![Cr(s)\rightarrow Cr^(3+)(aq)+3e^-](https://img.qammunity.org/2020/formulas/chemistry/middle-school/1rb0dqeldvj5ekppiaut5qfdqldi4l86jp.png)
Explanation :
Redox reaction : It is a reaction in which the oxidation and reduction reaction takes place simultaneously.
Oxidation reaction : It is a reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.
Reduction reaction : It is a reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.
The correct oxidation-half reaction will be :
![Cr(s)\rightarrow Cr^(3+)(aq)+3e^-](https://img.qammunity.org/2020/formulas/chemistry/middle-school/1rb0dqeldvj5ekppiaut5qfdqldi4l86jp.png)
In this half oxidation reaction, the oxidation state of 'Cr' changes from (0) to (+3) that means the oxidation state increases that means it shows oxidation.