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What is the roots of x in 8x2 +4=12​

User Amarilys
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1 Answer

4 votes

Answer:


\large\boxed{x=-1\ \vee\ x=1}

Explanation:


8x^2+4=12\qquad\text{subtract 4 from both sides}\\\\8x^2+4-4=12-4\\\\8x^2=8\qquad\text{divide both sides by 8}\\\\(8x^2)/(8)=(8)/(8)\\\\x^2=1\to x=\pm\sqrt1\\\\x=-1\ \vee\ x=1

User Jithin Pavithran
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