An X-ray tube emits X-rays with a wavelength of 1.0 X 10^-11 m. Determine the energy, in electron volts, possessed by the incident electrons

Question

asked May 9, 2020 105k views

1 Answer

Edgar Domingues · Answer 1 · 2020-05-14T04:43:25+0000

Answer:

$1.25\cdot 10^5 eV$

Step-by-step explanation:

The energy of the incident electron is equal to the energy acquired by the X-rays photon emitted by the tube, which is given by

$E=(hc)/(\lambda)$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength

In this problem, the wavelength of the photon is

$\lambda=1.0\cdot 10^(-11) m$

Therefore, the energy is

$E=((6.63\cdot 10^(-34) Js)(3\cdot 10^8 m/s))/(1.0\cdot 10^(-11) m)=2.0\cdot 10^(-14) J$

And keeping in mind that

$1 eV = 1.6\cdot 10^(-19) J$

We find the energy in electron volts:

$E=(2.0\cdot 10^(-14)J)/(1.6\cdot 10^(-19) J/eV)=1.25\cdot 10^5 eV$