Answer:
49.2 miles
Explanation:
The distance remains the same. d
The time spent on the outbound trip is t1 = -------------
35 mph
and that on the inbound (return) trip is
d
t2 = -------------
45 mph
We combine these two fractions and set the sum = to 2.5 hours:
d(1/35 + 1/45) = 5/2
We wish to solve for d, the distance between home and work.
The LCD of 35, 45 and 2 is 630.
1/35 becomes 18/630; 1/45 becomes 14/630, and 5/2 becomes 1575/630. Then we have the simpler equation d(18 + 14) = 1575, or
d(32) = 1575, and d is then
d = 1575/32 = 49.2 miles