As we can see on the picture we have a rectangle and half of circle.
The areas for half circle and rectangle are:
![</p><p>A_(rectangle)=a\cdot b \\</p><p>A_(halfcircle)=(A_(circle))/(2)=(\pi r^2)/(2)</p><p>](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w10hh6szk24boajcdr41ed92gki6ytgv7s.png)
The area of the figure is the sum of the area of half circle and rectangle. Also the height of a rectangle (6ft) is a diameter of a half circle therefore the radius of half circle is 6ft ÷ 2 = 3ft.
Now we calculate the areas.
![</p><p>A_(rectangle)=10\cdot 6=\underline{60} \\</p><p>A_(halfcircle)=(3.14\cdot3^2)/(2)=\underline{14.13} \\</p><p>A_(total)=A_(rectangle)+A_(halfcircle) =60+14.13=\boxed{74.13\approx74}</p><p>](https://img.qammunity.org/2020/formulas/mathematics/middle-school/te8a6vo9i8r4cjxbjd9dyg6oqv9w9rdh1o.png)
The area of the figure is approximately 74ft squared.
Hope this helps.
r3t40