Question

A circular swimming pool has a radius of 15 ft. There is a path all around that pool that is three feet wide.

What is the circumference of the outer edge of the path around the pool? Use 3.14 for pi
56.52 ft
94.20 ft
113.04 ft
114.04 ft

Answer 1

Pi•r^2

Radius= 15
Plug in and that should give you the blue area. =706.858

If you added 3 feet to the circle that would change the radius to 18 so back to the formula...
Pi•18^2
=1,017.876

To find the shades you would have to subtract the two and get your answer

Interesting. Either the answer choices are wrong or I am.... is the formula right? Lol it’s been too long

Answer 2

the circumference of the outer edge of the path around the pool is 113.04 ft

Explanation:

Hello, I think I can help you with this

the circumference is given by:

S=2π*r

where, S is the length of the circumference,π=3.14159.., r= radius

Step one

define the radius

the total radius of the pool and the path is

radius=15 ft + 3 ft

radius=18 ft

Step two

π=3.14

radius=18 ft

put the values into the equation

S=2π*r

S=2*3.14*18 ft

S=113.04 ft

the circumference of the outer edge of the path around the pool is 113.04 ft

I hope it helps, Have a nice day.