Question

A space shuttle is flying north at 6,510 m/s. It

then begins accelerating at 28.4 m/s² directly
northeast to properly align its path towards
orbit around the Earth. After 60.0 s, what is
the magnitude of its velocity?
Vf = [?] m/s
a
Vf

Answer 1

Answer: 81.1 for the direction of its velocity and 7808 for the magnitude of its velocity

Step-by-step explanation:

Answer 2

7808 m/s

Step-by-step explanation:

Find NE velocity after 60 s of acceleration in that direction:

= a t = 28.4 m/s^2 * 60 s = 1704 m/s

Vertical component = 1704 sin 45 = 1204.9 m/s

Horiz component = 1704 cos 45 = 1204.9 m/s

Add the two vertical components

6510 + 1204.9 = 7714.9 m/s = vertical velocity

Pythagorean theorem to find resultant of vertical and horiz v's

Vf ^2 = 1204.9^2 + 7714.9^2 0

Vf = 7808. m/s