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can anyone help me with this ??

can anyone help me with this ??-example-1
User SeanPONeil
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1 Answer

8 votes

Answer:

A. 336

B. Arranging 3 people in 8 chairs.

C. 42

B. Arranging 2 people in 7 chairs.

Explanation:

A.


P(n, r) = P(8, 3)

Formula for Permutation is given as:


P(n, r) = (n!)/((n-r)!)

Putting the value of
n = 8 and
r =3 , we get:


P(8, 3) = (8!)/((8-3)!) \\\Rightarrow (8* 7 * 6 * 5* 4 * 3 * 2* 1)/(5* 4 * 3* 2* 1)\\\Rightarrow 8* 7 * 6 \\\Rightarrow 336

B. Real world situation for part A:

Arranging 3 people on 8 chairs.

First person has 8 options.

Second person has 7 options.

Third person has 6 options.

C.


P(n, r) = P(7, 2)

Formula for Permutation is given as:


P(n, r) = (n!)/((n-r)!)

Putting the value of
n = 7 and
r = 2 , we get:


P(7, 2) = (7!)/((7-2)!) \\\Rightarrow (7 * 6 * 5* 4 * 3 * 2* 1)/(5* 4 * 3* 2* 1)\\\Rightarrow 7 * 6 \\\Rightarrow 42

D. Real world situation for part AC:

Arranging 2 people on 7 chairs.

First person has 7 options.

Second person has 6 options.

User Farhana
by
7.9k points

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