Answer:
<ADB = 70°
Explanation:
Given: AD bisects <CAB and <CAB = 80° then <CAD = < DAB = 80/2 = 40°
ΔADB is an isosceles triangle so <ABD = <ADB
So
<ADB = 1/2 (180 - 40)
<ADB = 1/2 (140)
<ADB = 70° also <ABD = <ADB = 70°
Answer
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