Question

Find the value of x. Round to the nearest tenth.
Please help me!!

Answer 1

x ≈ 4.4 in

Explanation:

The segment from the centre to the chord is a perpendicular bisector.

The third side of the right triangle = 7.4 ÷ 2 = 3.7

Consider the right triangle with legs 3.7 and 2.4 and hypotenuse x

Using Pythagoras' identity

x² = 2.4² + 3.7² = 5.76 + 13.69 = 19.45

Take the square root of both sides

x =
`√(19.45)` ≈ 4.4