Answer:
[4, 8]
Explanation:
You want to find t such that ...
T ≥ 69
24t − 2t^2 + 5 ≥ 69
t^2 -12t +32 ≤ 0 . . . . . subtract the left side, divide by 2
(t -4)(t -8) ≤ 0 . . . . . . . factor
The factors will have different signs, so their product will be negative, for values of t between 4 and 8. Of course, the equality holds at t=4 and t=8, so the solution interval is ...
t ∈ [4, 8]