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which point lies outside the circle with equation (x - 2) + (y + 3) = 4 (1, -4 ) ( 0, -3 ) ( 2, 0 ) (2, -4 )

User Igo
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1 Answer

1 vote

Answer:

The point (2,0) is outside the circle

Explanation:

we have


(x-2)^(2)+(y+3)^(2)=4


(x-2)^(2)+(y+3)^(2)=2^(2)

This is the equation of a circle with center at (2,-3) and radius equal to 2 units

Using a graphing tool

Plot the circle and the given points and verify if the point lie outside the circle

we have


(1, -4 ),(0, -3),(2, 0),(2,-4)

so

The point (2,0) is outside the circle

see the attached figure

which point lies outside the circle with equation (x - 2) + (y + 3) = 4 (1, -4 ) ( 0, -3 ) ( 2, 0 ) (2, -4 )-example-1
User Srusti Thakkar
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7.4k points