Answer:
157 g of MgO
Step-by-step explanation:
the reaction:
2Mg + O2 ➡️ 2MgO
1) find the mol of Mg
mol = mass / molar mass
mass = 94.2 g
molar mass = 24
mol = 94.2 / 24
mol = 3.925 mol
2 mol = 3.925 moles
2) find mass of MgO
mass = mol × molar mass
mol = 3.925
molar mass = 24+16 = 40
mass = 3.925 × 40
= 157 g