What are the roots of f(x) = x2 - 48? -48 and 48 -24 and 24 -8/5 and 83 -4,3 and 43

asked Sep 4, 2020 98.0k views

4 votes

What are the roots of f(x) = x2 - 48?

-48 and 48
-24 and 24
-8/5 and 83
-4,3 and 43

by Taran

5.1k points

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3 votes

Answer:

It is D

Explanation:

I just took the test

Jeffrey Chen answered Sep 6, 2020

4.5k points

3 votes

Answer: 4sqrt(3), -4sqrt(3)

x^2-48=0
x^2=48
x=+/-sqrt(48)=4sqrt(3),-4sqrt(3)

Rory Solley answered Sep 10, 2020

4.8k points

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