Question

A dog running to the right at 4 m/s sees a ball and accelerates steadily to catch it. The dog accelerates to the right at a rate of 0.21 m/s^2 and catches the ball after 3.8s. What was the dogs velocity when it caught the ball? *Assume here that running to the right is positive and running to the left is negative.

A- 7.96
B- 10.569
C- 6.782
D- 4.798
E- none

Answer 1

D.-4.798m/s

Step-by-step explanation:

Greetings !

Given values

`u= 4ms \\ a = 0.21ms {}^(2) \\ t = 3.8sec`

Solve for V of the given expression

Firstly, recall the velocity-time equation

`v = u + at`

plug in known values to the equation

`v = (4) + (0.21)(3.8)`

solve for final velocity

`v = 4.792ms`

Hope it helps!