2 Answers

DylanYoung · Answer 1 · 2020-03-12T21:26:22+0000

5. Let x be the missing angle.

We have the hypotenuse of the given right angle triangle to be 27 units.

The opposite side to the missing angle is 11 units.

We use the sine ratio to obtain:

$\sin x=(Opposite)/(Hyppotenuse)$

$\sin x=(11)/(27)$

$x=\sin^(-1)((11)/(27))$

$x=24.04\degree$ to the nearest hundredth.

6. Let y represent the missing angle.

We have the hypotenuse of the given right angle triangle to be 24 units.

The opposite side to the missing angle is 12 units.

We use the sine ratio to obtain:

$\sin y=(Opposite)/(Hyppotenuse)$

$\sin y=(12)/(24)$

$y=\sin^(-1)((1)/(2))$

$y=30\degree$ .

7. Let the missing angle be z.

This time we have the adjacent side to be 13 units and the hypotenuse is 20 units.

We use the cosine ratio to obtain:

$\cos z=(Adjacent)/(Hypotenuse)$

This implies that:

$\cos z=(13)/(20)$

$z=\cos ^(-1)((13)/(20))$

$z=49.46\degree$ to the nearest hundredth

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