Question

Please help I’m lost

Answer 1

5. 24°

6. 30°

7. 49°

Explanation:

5. You are given right triangle with known opposite leg and hypotenuse. By the sine definition,

`\sin \theta=\frac{\text{opposite leg}}{\text{hypotenuse}}=(11)/(27)\\ \\\theta=\sin^(-1)\left((11)/(27)\right)\approx 24^(\circ)`

6. You are given right triangle with known opposite leg and hypotenuse. By the sine definition,

`\sin \theta=\frac{\text{opposite leg}}{\text{hypotenuse}}=(12)/(24)=(1)/(2)\\ \\\theta=\sin^(-1)\left((1)/(2)\right)\approx 30^(\circ)`

7. You are given right triangle with known adjacent leg and hypotenuse. By the cosine definition,

`\cos \theta=\frac{\text{adjacent leg}}{\text{hypotenuse}}=(13)/(20)\\ \\\theta=\cos^(-1)\left((13)/(20)\right)\approx 49^(\circ)`