Question

The rectangle below has an area of 30k3 + 6k2.

The width of the rectangle is equal to the greatest common monomial factor of 30k3 and 6k2.
What is the length and width of the rectangle?

Answer 1

Width = 6k²

Length = 5k+1

Explanation:

Given the area of a rectangle expressed as

A = 30k³ + 6k²

Get the greatest common factor

30k³ = (2 * 3 * k²) * k * 5

6k² = (2 * 3 * k²)

The common factor is the value in bracket i.e 2 * 3 * k² = 6k²

Width of the rectangle = 6k²

Get the length

A = LW

L = A/W

L = 30k³ + 6k²/6k²

L = 6k²(5k+1)/6k²

L = 5k + 1

Hence the length L = 5k+1