Question

If BD = 16 yd and the area of rhombus ABCD is 72 yd^2, what is AC?

Answer 1

Formula for finding area of rhombus:
`(d1 * d2)/(2)`

d₁ = 16 yd

Area = 72 yd²

Rhombus Area =>

`(16 * d2)/(2) = 72`

16*d₂ = 144

d₂ = 9

AC = 9 yd

Hope it helps!