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300 children are divided into 2 groups. There are 50 more children in the first group than in the 2nd group. How many children are there in the 2nd group?

User GorvGoyl
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4.8k points

2 Answers

4 votes

Hei there!

Let's start by letting x be the number of children in the 2nd group. So we can make an equation:

(50+x)+x=300

Next, open parenthesis and combine like terms. Then solve for x.

50+x+x=300

2x=300-50

2x=250

x=125

So, there are 125 kinds in the 2nd group.

Hope I helped, sorry if I'm wrong ouo.

~Potato.

Copyright Potato 2019.

User Ben Collier
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5.2k points
4 votes

Answer: 125 children

We have an unknown amount of children in the second group, so let us call this x. The number of children in the first class must be x + 50. In other words, the total number of children in both classes would be x + x + 50, which equals to 2x+50, and you have a total of 300 children. Let us start with this equation:

2x + 50 = 300

Subtract 50 from both sides

2x + 50 - 50 = 300 - 50

Simplify

2x = 250

Divide both sides by 2

2x / 2 = 250 / 2

Simplify

x = 125

Again, we said, x is an unknown amount of children in the second group. As you can see, x = 125, so there are 125 children in the second group.

125 + 50 = 175

Since, there are 50 more children in the first group, you would add 50 to 125, and that will give us a total of 175 children in the first group.

User Jocelyn Delalande
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5.4k points