Answer:
-3
Explanation:
In order to find the smallest zero, we will have to find out all the zeros of the function.
In case you are wondering what a zero is, it is the x-value or the domain intersections. The points where the parabola intersects the x-axis.
4x² - 8x - 60 = 0
Why zero?
We know that the parabola intersects the x-axis and when it does, the y-value is 0. h(x) is nothing but 'y'.
4(x²-2x-15) = 0 → I took the gcd as 4 and did it accordingly.
x² - 2x - 15 = 0 → Divide on both sides with 4
Now, what multiples to -15 but adds up to -2?
-5 and 3
x² + 3x - 5x - 15 → Grouping the terms
x ( x + 3 ) - 5 ( x + 3 ) → Taking the GCD in both groups
( x - 5 ) ( x + 3 ) = 0
x = 5 , -3
The smallest one out of these zeros is -3.
Hope it helps! :)