Answer:
28%
Explanation:
From the table, the probability that the person will have
- 0 credit cards - 0.16;
- 1 credit card - 0.12;
- 2 credit cards - X;
- 3 credit cards - Y;
- 4 credit cards - 0.72
The sum of all probabilities must equal to 1, so

The probability that a person will have at most 3 credit cards is

and as a percentage 28%