Question

Please help i don't have alot time ​

Answer 1

`g\left(x\right)=-√(x+3)+8`

Explanation:

Given function is
`f\left(x\right)=-2√(x-3)+8`.

Now let's find it's range.

we know that square root function always gives positive output then:

`√(x-3)\ge0`

`-2√(x-3)\le-2\left(0\right)`

`-2√(x-3)\le0`

`-2√(x-3)+8\le0+8`

`-2√(x-3)+8\le 8`

`f(x) \le 8`

Hence range of the function is
`(-\infty,8]`.

we can repeat same process to find the range of all the given choices.

we will find that only 3rd choice has same range.

Hence final answer is
`g\left(x\right)=-√(x+3)+8`