Question

Antoine has $18.20 to spend on some oranges and a pumpkin. Oranges cost

$1.30 per pound, and a pumpkin costs $5.20
The inequality 1.30x + 5.20 18.20 models this situation, where x is the
number of pounds of oranges.
Solve the inequality. How many pounds of oranges can Antoine buy?

Answer 1

10 pounds

Explanation:

You forgot the inequality sing, but since Antoine can't spend more than $18.20, I am positive that the sign is
`\leq` (Antony can spend $18.20 or less than $18.20).

Therefore, our inequality is:
`1.30x+5.20\leq 18.20`

where
`x` is the pounds of oranges

Let's solve step-by-step to find how many pounds of oranges he can buy

Step 1. Subtract 5.20 fro both sides of the inequality

`1.30x+5.20-5.20\leq 18.20-5.20`

`1.30x\leq 13`

Step 2. Divide both sides of the inequality by 1.30

`(1.30x)/(1.30) \leq (13)/(1.30)`

`x\leq 10`

We can conclude that Antony can buy 10 pounds of oranges.