Question

When 7.50 l of sulfur trioxide are produced by the reaction of sulfur dioxide in an excess of oxygen at standard temperature and pressure, how many liters of sulfur dioxide were used? 2so2 (g) + o2 (g) yields 2so3 (g)?

Answer 1

7.50

Step-by-step explanation:

Answer 2

`\boxed{\text{7.50 L SO}_(2)}`

Step-by-step explanation:

For this problem, we must use Gay-Lussac's Law of Combining Volumes:

The ratio in which gases react is the same as the ratio of their coefficients in the balanced equation.

The balanced equation is

Theor: 2 L 2 L

2SO₂ + O₂ ⟶2 SO₃

V/L: 7.50

Gay-Lussac's Law tells us that 2 L of SO₂ form 2 L of SO₃.

The volume of SO₂ used was

`V = \text{7.50 L SO}_(3) * \frac{\text{2 L SO}_(2)}{\text{2 L SO}_(3)}\\\\V = \boxed{\textbf{7.50 L SO}_(2)}`