Question

P-xylene, c8h10, has an enthalpy of fusion of 158.3 j g-1 and its melting point temperature is 13.2°c. how much heat is required to transform 115 g of solid p-xylene at 13.2°c into liquid p-xylene, also at 13.2°c?

Answer 1

`\boxed{\text{18.2 kJ}}`

Step-by-step explanation:

The formula for the heat involved is

`q = m\Delta_{\text{f}}\text{H}`

Data:

m = 115 g

`\Delta_{\text{f}}\text{H} = \text{158.3 J/g}`

Calculation:

`q = \text{115 g} * \frac{\text{158.3 J}}{\text{1 g}}\\\\q = \text{18 200 J} = \textbf{18.2 kJ}}\\\\\text{It takes }\boxed{\textbf{18.2 kJ}} \text{ to melt the p-xylene}`