Question

. percent iron in a mixture that is 52.2% Fe2O3​

Answer 1

36.51%.

Step-by-step explanation:

First find the percentage of iron in pure Fe2O3 using the atomic masses of the elements:

= (2 * 55.845) * 100 / (2*55.845+ 3*15.999)

= 69.94 %.

So the percentage of iron in the mixture

= 52.2 * 0.6994

= 36.51 (answer).