Question

Suppose that ym has length 12 in. and its distance from point L is 5 in. Find the radius of ⊙L to the nearest tenth.

Answer 1

The radius of circle L is
`7.8\ in`

Explanation:

Remember that a line that passes through the center divide the circle into two equal parts

YV=VM=6 in

VL is perpendicular to YM

so

The triangle VLM is a right triangle

The radius is equal to LM ----> hypotenuse of the triangle VLM

Applying the Pythagoras Theorem

`LM^(2)=VM^(2)+VL^(2)`

substitute the given values

`LM^(2)=6^(2)+5^(2)`

`LM^(2)=61`

`LM=7.8\ in`