Question

How much heat is absorbed by a 67g iron skillet when its temperature rises from 14oC to 22oC?

Answer 1

Answer:237.98 J

Step-by-step explanation:

The heat (thermal energy) absorbed by the iron skillet can be found using the following equation:

`Q=m.C.\Delta T` (1)

Where:

`Q` is the heat

`m=67 g` is the mass of the element (iron in this case)

`C` is the specific heat capacity of the material. In the case of iron is
`C=0.444(J)/(g\°C)`

`\Delta T=T_(f)-T_(i)=22\°C - 14\°C= 8\°C` is the variation in temperature

Knowing this, lets rewrite (1) with these values:

`Q=(67 g)(0.444(J)/(g\°C))(8\°C)` (2)

Finally:

`Q=237.98 J`