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If f(x) = –2x+8 and g(x) = Square root of X+7,
what is (fºg)(2)

1 Answer

6 votes

Answer:

(fog)(2)=2

Explanation:

Given

f(x)= -2x+8

and

g(x)= √(x+7)

For finding (fog)(2), we have to find (fog)(x) first

In order to find (fog)(x) we will put the value of g(x) in f(x) in place of x.

(fog)(x)= -2g(x)+8

Putting the value of g(x)

(fog)(x)= -2√(x+7)+8

We have to find (fog)(2), so we have to put at the place of x in the composition

(fog)(x)= -2√(2+7)+8

(fog)(x)= -2√9+8

= -2(3)+8

= -6+8

=2

So,

(fog)(2)=2 ..

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