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Calculate the number of moles of methane (CH4)needed to produce 7.84 g of water (H2O).​

User Bluebadge
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Answer:

0.218 mol.

Step-by-step explanation:

  • Firstly, we need to write the balanced reaction:

CH₄ + 2O₂ → CO₂ + 2H₂O,

It is clear that 1 mol of CH₄ reacts with 2 mol of O₂ to produce 1 mol of CO₂ and 2 mol of H₂O.

  • We need to calculate the no. of moles of 7.84 g H₂O:

n = mass/molar mass = (7.84 g)/(18.0 g/mol) = 0.436 mol.

Using cross multiplication:

1 mol of CH₄ is needed to produce → 2 mol of H₂O, from stichiometry.

??? mol of CH₄ is needed to produce → 0.436 mol of H₂O.

∴ The no. of moles of CH₄ = (1 mol)(0.435 mol)/(2 mol) = 0.218 mol.

User DexXxed
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