Question

What are the center and radius of the circle with equation (x-7)^2 + (y+5)^2 = 36?

Answer 1

Center (7, -5) and radius=6

Explanation:

The question is on center and radius of a circle

The general circle equation is given as (x-h)² + (y-k)²= r² where the center is (h,k) and radius is r

Given (x-7)^2 + (y+5)^2 = 36?

(x-7)² + (y+5)²= 6²

h=7 and y=-5 and r=6

Answer 2

Center:(7,-5)

Radius:r=6

EXPLANATION

The given circle has equation;

`{(x - 7)}^(2) + {(y + 5)}^(2) = 36`

We can rewrite this as:

`{(x - 7)}^(2) + {(y - - 5)}^(2) = {6}^(2)`

Comparing this to the standard equation of the circle:

`{(x - h)}^(2) + {(y - k)}^(2) = {r}^(2)`

we have h=7,k=-5, and r=6.

Therefore the center (h,k)=(7,-5) and the radius is r=6.