Answer:
3x(x - 1)(x - 3)
Explanation:
the sum of the coefficients = 3 - 12 + 9 = 0
hence x = 1 is a root of f(x) and (x - 1) is a factor
dividing 3x³ - 12x² + 9x gives
f(x) = (x - 1)(3x² - 9x)
= (x - 1)3x(x - 3) = 3x(x - 1)(x - 3) ← in factored form
f(x) = 3x(x-1)(x-3)
f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =
= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =
= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)
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