Question

If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

Answer 1

`(g \circ \: f)(0) = - 216`

Step-by-step explanation

The functions are:

`f(x) = 2x - 6`

`g(x) = {x}^(3)`

`(g \circ \: f)(x) =g(f(x))`

`(g \circ \: f)(x) =g(2x - 6)`

We substitute f(x) into g(x) to obtain:

`(g \circ \: f)(x) =(2x - 6)^(3)`

We now substitute x=0 to obtain;

`(g \circ \: f)(0) =(2(0) - 6)^(3)`

`(g \circ \: f)(0) =(- 6)^(3)`

This simplifies to:

`(g \circ \: f)(0) = - 216`