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If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

User Cwick
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2 Answers

3 votes

Answer:

Step-by-step explanation:216

User ZbMax
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6.9k points
2 votes

Hello!

The answer is:


(g\circ f)(0)=-216

Why?

To composite functions, we need to evaluate functions in another function(s), for example:

Given f(x) and g(x), if we want to calculate f(x) composite g(x), we need to evaluate g(x) into f(x).

So, we are given the functions:


f(x)=2x-6\\g(x)=x^(3)

And we are asked to calculate g(x) composite f(x), and then evaluate "x" to 0, so, calculating we have:


(g\circ f)(x)=g(f(x))\\\\(g\circ f)(x)=(2x-6)^(3)

Now that we have the composite function, we need to evaluate "x" equal to 0, so:


(g\circ f)(0)=(2x-6)^(3)\\\\(g\circ f)(0)=(2*(0)-6)^(3)=(0-6)^(3)=-6*-6*-6=-216

Hence, we have that:


(g\circ f)(0)=-216

Have a nice day!

User Jamix
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6.1k points
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