Answer:
The solution to this system is (-2,1)
Explanation:
The given system of equations is;
...eqn1
and
....eqn2
We make y the subject of the second equation to get:

...eqn3
We put eqn3 into eqn1 to get;

We expand to get:


Simplify both sides to get:

Put x=-2 into eqn3


The solution to this system is therefore (-2,1)