Question

Find the mass of 3.50x10^23 molecules of nitrogen gas

Answer 1

16.27 g.

Step-by-step explanation:

• It is known that every 1.0 mol of a compound contains Avogadro's no. of molecules (6.022 x 10²³).

Using cross multiplication:

1.0 mol of N₂ gas contains → 6.022 x 10²³ molecules.

??? mol of N₂ gas contains → 3.50 x 10²³ molecules.

∴ The no. of moles of N₂ gas = (1.0 mol)(3.50 x 10²³ molecules)/(6.022 x 10²³ molecules) = 0.5812 mol.

∴ The mass of 3.50 x 10²³ molecules of N₂ gas = (no. of moles)*(molar mass) = (0.5812 mol)(28.0 g/mol) = 16.27 g.