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Please help me with this!!

Please help me with this!!-example-1
User Jindra
by
6.7k points

1 Answer

3 votes

Explanation:

To find the y-coordinate points we need to evaluate the function for all the
x values in the table. In other words, we need to replace
x with each value in our given function and simplify.

- For x = 0


f(x)=(x-2)^2-5


f(0)=(0-2)^2-5


f(0)=(-2)^2-5


f(0)=4-5


f(x)=-1

Since
x=0 and
y=-1, our first point is (0, -1)

- For x = 1


f(x)=(x-2)^2-5


f(1)=(1-2)^2-5


f(1)=(-1)^2-5


f(1)=1-5


f(x)=-4

Our second point is (1, -4)

- For x = 2


f(x)=(x-2)^2-5


f(2)=(2-2)^2-5


f(2)=(0)^2-5


f(x)=-5

Our third point is (2, -5)

- For x = 3


f(x)=(x-2)^2-5


f(3)=(3-2)^2-5


f(3)=(1)^2-5


f(3)=1-5


f(x)=-4

Our fourth point is (3, -4)

- For x = 4


f(x)=(x-2)^2-5


f(4)=(4-2)^2-5


f(4)=(2)^2-5


f(4)=4-5


f(x)=-1

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

Please help me with this!!-example-1
User Jakobht
by
6.4k points