Question

a man is three times as old as his son. In ten years time, the man will be two times as old as his. Find the age of the son and the father

Answer 1

age of son= X

Father's age =3x

After 10 years , father's age= 3x +10

Son's age = X+10

Operations:

3x + 10 =2(x + 10 )

3x + 10 = 2x + 20

X= 10

Therefore, present age of son= 10 years

Father's present age = 30 years

After 10 years son will be 20 years and the father 40 yes which is double