Question

If a nichrome wire has a resistance of 15Ω and is connected across the terminals of a 3.0 V flashlight battery, how much current is in the wire?

1.0 amps
5.0 amps
7.5 amps
0.20 amps

Answer 1

0.20 A

Step-by-step explanation:

The current in the wire is given by Ohm's law:

`I=(V)/(R)`

where

I is the current

V is the voltage

R is the resistance

In this problem,

V = 3.0 V is the voltage

`R=15 \Omega` is the resistance

Substituting into the formula,

`I=(3.0 V)/(15 \Omega)=0.20 A`